A charged particle of specific charge α moves with a velocity →v=v0^i in a magnetic field →B=B0√2(^j+^k). Then : (specific charge = charge per unit mass)
A
path of the particle is a helix
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B
path of the particle is a circle
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C
distance moved by particle intime t=πB0αisπv0B0α
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D
velocity of particle after time t=πB0αis(v02^i+v02^j)
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Solution
The correct options are B distance moved by particle intime t=πB0αisπv0B0α C path of the particle is a circle 1) Path of particle in magnetic field is either circular, straight line or helix, Here charged particle is projected at an angle so path must be circular. 2) ¯¯¯v=v0¯i ¯¯¯¯F=q(¯¯¯vׯ¯¯¯B) ¯¯¯¯F=q(v0¯i×B√2(¯j+¯¯¯k)) ¯¯¯¯F=qv0B√2(¯¯¯k−¯j) Distance travelled by particle in time t=v⋅t=v0⋅πB0α