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Question

A charged particle of specific charge α moves with a velocity v=v0^i in a magnetic field B=B02(^j+^k). Then : (specific charge = charge per unit mass)

A
path of the particle is a helix
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B
path of the particle is a circle
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C
distance moved by particle intime t=πB0α is πv0B0α
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D
velocity of particle after time t=πB0αis(v02^i+v02^j)
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Solution

The correct options are
B distance moved by particle intime t=πB0α is πv0B0α
C path of the particle is a circle
1) Path of particle in magnetic field is either circular, straight line or helix, Here charged particle is projected at an angle so path must be circular.
2)
¯¯¯v=v0¯i
¯¯¯¯F=q(¯¯¯vׯ¯¯¯B)
¯¯¯¯F=q(v0¯i×B2(¯j+¯¯¯k))
¯¯¯¯F=qv0B2(¯¯¯k¯j)
Distance travelled by particle in time
t=vt=v0πB0α

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