Question

A charged particle revolves in circular path in uniform magnetic field after accelerating by a potential difference of V volts.Choose the correct options if V is doubled.

• A. kinetic energy of particle will become two times.
• B. radius in circular path will become two times
• C. radius in circular path will become $\sqrt{2}$ times
• D. angular velocity will remain unchanged

Answer 1

Answer: (A), (C), (D)

kinetic energy of particle will become two times.
angular velocity will remain unchanged
radius in circular path will become $\sqrt{2}$ times

$KE=qV$ or $KE\infty V$

$r=\frac{\sqrt{2qVm}}{Bq}$ or $r\propto \sqrt{V}$

$T=\frac{2\pi m}{Bq}$

or T is independent of V.