A cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to distances less than 500 m. If a cheetah spots his prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h ?

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Solution

The correct option is A 4s
Average velocity of cheetah = $90 {k m h}^{- 1}$
= $90 \times \frac{5}{18} {m s}^{- 1}$
= $25 m s^{- 1}$
$T i m e t a k e n = \frac{D i s t a n c e C o v e r e d}{A v e r a g e v e l o c i t y}$
Time Taken = $\frac{100 m}{25 m s^{- 1}}$
Time taken = $4 s$

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A cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to distances less than 500 m. If a cheetah spots his prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h ?

The correct option is A 4sAverage velocity of cheetah = 90kmh−1 = 90×518ms−1 = 25ms−1 Timetaken=DistanceCoveredAveragevelocity Time Taken = 100m25ms−1 Time taken = 4s

The correct option is A 4s
Average velocity of cheetah = $90 {k m h}^{- 1}$
= $90 \times \frac{5}{18} {m s}^{- 1}$
= $25 m s^{- 1}$
$T i m e t a k e n = \frac{D i s t a n c e C o v e r e d}{A v e r a g e v e l o c i t y}$
Time Taken = $\frac{100 m}{25 m s^{- 1}}$
Time taken = $4 s$