A cheetah, the fastest of all land animals over a short distance, accelerates from rest to $26 m s^{- 1}$ . Assuming that the acceleration is constant, find the average speed of the cheetah.

13 m s^{- 1}

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9 m s^{- 1}

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11 m s^{- 1}

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10 m s^{- 1}

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Solution

The correct option is D $13 m s^{- 1}$
$v = 26 = u + a t = a t$
$a t = 26$
$s = u t + \frac{1}{2} a t^{2}$
Average velocity is $\frac{s}{t} = u + \frac{1}{2} a t = 0 + \frac{1}{2} \times 26 = 13 m s^{- 1}$

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A cheetah, the fastest of all land animals over a short distance, accelerates from rest to 26 ms−1. Assuming that the acceleration is constant, find the average speed of the cheetah.

The correct option is D 13 ms−1v=26=u+at=atat=26s=ut+12at2Average velocity is st=u+12at=0+12×26=13 ms−1

A cheetah, the fastest of all land animals over a short distance, accelerates from rest to $26 m s^{- 1}$ . Assuming that the acceleration is constant, find the average speed of the cheetah.

The correct option is D $13 m s^{- 1}$
$v = 26 = u + a t = a t$
$a t = 26$
$s = u t + \frac{1}{2} a t^{2}$
Average velocity is $\frac{s}{t} = u + \frac{1}{2} a t = 0 + \frac{1}{2} \times 26 = 13 m s^{- 1}$