A cheetah, the fastest of all land animals over a short distance, accelerates from rest to $26 m / s$ . Assuming that the acceleration is constant, find the average speed of the cheetah.

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Solution

Step 1: Given data
Initial Velocity ( $u$ ) of cheetah = $0 m / s .$
Final velocity ( $v$ ) of cheetah = $26 m / s .$
acceleration is constant.
Step 2: calculating average speed
$A v e r a g e s p e e d = \frac{i n i t i a l v e l o c i t y + f i n a l v e l o c i t y}{2} = \frac{(u + v)}{2} = (\frac{0 + 26}{2}) = 13 m / s .$
Hence, the average speed of cheetah is $13 m / s .$

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A cheetah, the fastest of all land animals over a short distance, accelerates from rest to 26m/s. Assuming that the acceleration is constant, find the average speed of the cheetah.

Step 1: Given dataInitial Velocity (u) of cheetah = 0m/s.Final velocity (v) of cheetah = 26m/s.acceleration is constant.Step 2: calculating average speedAveragespeed=initialvelocity+finalvelocity2=(u+v)2=(0+262)=13m/s.Hence, the average speed of cheetah is 13m/s.

A cheetah, the fastest of all land animals over a short distance, accelerates from rest to $26 m / s$ . Assuming that the acceleration is constant, find the average speed of the cheetah.