Question

A chemical reaction is given below:
$2O_3\to 3O_2$. This reaction obeys the following mechanism:
$O_3\to O_2+\left[O\right]\left(fast\right)$
In this reaction, order with respect to $O_2$ is:

• A. 3
• B. -2
• C. -1

Answer 1

The correct option is C -1

$\frac{-d\left[O_3\right]}{dt}=k\frac{[O_3{]}^2}{\left[O_2\right]}$
Hence, order with respect to $O_2$ is -1.