A chemical reaction procceds into the following steps,Step I, 2A⇌X (fast)Step II, X+B→Y (slow)Step III, Y+BA⇌X [Product] (fast)The rate law for the overall reaction is:
A chemical reaction proceeds into the following steps
stepI, 2AX fast
step II, X+BY slow
step III, Y+B Product fast
The rate law for the overall reaction is ?
For a single step reaction to the type A + 2B → E + 2F
A reaction takes place in three steps. The rate constant of the three steps are k1,k2 and k3 respectively. The overall rate constant k=k1k3k2. The energy of activation for the three steps are 40, 30 and 20 kJ respectively. Therefore: