A chemist has 10 liters of a solution that is 10 percent nitric acid by volume. He wants to dilute to solution to 4 percent strength by adding water. How many liters of water must he add ?

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Solution

The correct option is A 15
We see that 0.1 x 10 = 1 liter is nitric acid. We can let w = amount of water that must be added to dilute the solution to 4%:
4/100 = 1/(10 + w)
4(w + 10) = 100
w + 10 = 25
w = 15

Hence, the correct option is $A$ .

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A chemist has 10 liters of a solution that is 10 percent nitric acid by volume. He wants to dilute to solution to 4 percent strength by adding water. How many liters of water must he add ?

The correct option is A 15We see that 0.1 x 10 = 1 liter is nitric acid. We can let w = amount of water that must be added to dilute the solution to 4%:4/100 = 1/(10 + w)4(w + 10) = 100w + 10 = 25w = 15Hence, the correct option is A.

The correct option is A 15
We see that 0.1 x 10 = 1 liter is nitric acid. We can let w = amount of water that must be added to dilute the solution to 4%:
4/100 = 1/(10 + w)
4(w + 10) = 100
w + 10 = 25
w = 15

Hence, the correct option is $A$ .