Question

A chemist has 4 samples of artificial sweetener A,B,C and D. To identify these samples, he performed certain experiments and noted the following observations :
(i) A and D both form blue-violet colour with ninhydrin.
(ii) Lassaigne extract of C gives positive $AgN{O}_3$ test and negative $F{e}_4\left[Fe\right(CN{)}_6{]}_3$ test.
(iii) Lassaigne extract of B and D gives positive sodium nitroprusside test.
Based on these observations which option is correct ?

• A. A : Aspartame; B : Saccharin;
  C : Sucralose; D : Alitame
• B. A : Aspartame; B : Alitame;
  C : Saccharin; D : Sucralose
• C. A : Alitame; B : Saccharin;
  C : Aspartame; D : Sucralose
• D. A : Saccharin; B : Alitame;
  C : Sucralose; D : Aspartame

Answer 1

The correct option is A A : Aspartame; B : Saccharin;

C : Sucralose; D : Alitame
i) Blue voilet color with Ninhydrine → amino acid derivative. So it cannot be saccharide or sucralose.
(ii) Lassaigne extract give +ve test with $AgN{O}_3$ So $Cl$ is present, -ve test with $F{e}_4\left[Fe\right(CN{)}_6{]}_3$ means $N$ is absent. So it can't be Aspartame or Saccharine or Alitame, so$C$ is sucralose.
(iii) Lassaigne solution of B and D given +ve sodium nitroprusside test, so it is having $S$, so it is Saccharine and Alitame
A: Aspartame;

B : Saccharin;

C : Sucralose;

D : Alitame;