A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1, 2 and 3 contained colourless solutions, while Bottle 4 contained a blue solution. The labels from the bottles were lying scattered on the floor of the cupboard.They were : copper (II) sulphate, sodium carbonate, lead nitrate and hydrochloric acid.
By mixing samples of the contents of the bottles, in pairs, the chemist made the following observations:
(i) Bottle 1 + Bottle 2 : white precipitate
(ii) Bottle 1 + Bottle 3 : white precipitate
(iii) Bottle 1 + Bottle 4 : white precipitate
(iv) Bottle 2 + Bottle 3 : colorless gas evolved
(v) Bottle 2 + Bottle 4 : no visible reaction
(vi) Bottle 3 + Bottle 4 : blue precipitate
Colourless solution present in Bottle-1 is___________.
A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1, 2 and 3 contained colourless solutions, while Bottle 4 contained a blue solution. The labels from the bottles were lying scattered on the floor of the cupboard.They were : copper (II) sulphate, sodium carbonate, lead nitrate and hydrochloric acid.
By mixing samples of the contents of the bottles, in pairs, the chemist made the following observations:
(i) Bottle 1 + Bottle 2 : white precipitate
(ii) Bottle 1 + Bottle 3 : white precipitate
(iii) Bottle 1 + Bottle 4 : white precipitate
(iv) Bottle 2 + Bottle 3 : colorless gas evolved
(v) Bottle 2 + Bottle 4 : no visible reaction
(vi) Bottle 3 + Bottle 4 : blue precipitate
Colourless solution present in Bottle-1 is___________.
The correct option is C Pb(NO3)2
Bottle 1: lead-nitrate
Bottle 2: hydrochloric acid so
Pb(NO3)2+HCl→PbCl2 white ppt.
Bottle 1: lead-nitrate
Bottle 2: hydrochloric acid so
Pb(NO3)2+HCl→PbCl2 white ppt.
