A chemist wants to prepare diborane by the reaction. LiH+BF3→LiBF4+B2H6
If he starts with 2.0 moles each of LiH&BF3. Then, the correct option(s) is/are:
A
A maximum of 0.25 moles of B2H6 can be prepared
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B
More than 0.25 moles of B2H6 can be prepared
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C
Not more than 1.5 moles of LiBF4 can be prepared
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D
2 moles of LiBF4 can be prepared
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Solution
The correct option is C Not more than 1.5 moles of LiBF4 can be prepared Balanced reaction is 6LiH+8BF3→6LiBF4+B2H6
and
Here, BF3 is a limiting reagent.
Moles of B2H6 forms from 2 moles of BF3=28=0.25
Similarly, no. of LiBF4 that forms from 2 moles of BF3 = 68×2=1.5