wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A chemist wants to prepare diborane by the reaction.
LiH+BF3LiBF4+B2H6
If he starts with 2.0 moles each of LiH & BF3. Then, the correct option(s) is/are:

A
A maximum of 0.25 moles of B2H6 can be prepared
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
More than 0.25 moles of B2H6 can be prepared
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Not more than 1.5 moles of LiBF4 can be prepared
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2 moles of LiBF4 can be prepared
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Not more than 1.5 moles of LiBF4 can be prepared
Balanced reaction is
6LiH+8BF36LiBF4+B2H6
and
Here, BF3 is a limiting reagent.
Moles of B2H6 forms from 2 moles of BF3=28=0.25
Similarly, no. of LiBF4 that forms from 2 moles of BF3 = 68×2=1.5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Limiting Reagent
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon