A chemist wants to produce $C l_{2} (g)$ from molten $N a C l$ . How many grams could be produced if he uses a steady current of $2 a m p e r e$ for $2.5 m i n u t e s$ ?

3.55 g

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1.775 g

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0.110 g

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0.1175 g

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Solution

The correct option is B $0.110 g$
${C l}^{-} \to e^{-} + 0.5 {C l}_{2}$
charge passed $= 2 A \times 2.5 \times 60 s = 300 C$
moles of electron present $= \frac{300}{96500} = 0.0031 m o l e s$
0.5 moles of ${C l}_{2}$ are formed from 1 mole of electrons.
For 0.0031 moles of electrons 0.00155 moles of ${C l}_{2}$ are formed.
mass of ${C l}_{2} = 0.00155 \times 71 = 0.110 g$

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