A child drops a toy from the top of a building, it takes 1 s to reach the ground. Find the height of the building and the average speed of the toy? $T a k e g = 10 \frac{m}{s^{2}}$

4 m and 5 m/s

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5 m and 5 m/s

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6 m and 6 m/s

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7 m and 7 m/s

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Solution

The correct option is B
5 m and 5 m/s

Since,u = 0 and a = 10 m/s²
s = ut + $\frac{1}{2} a t^{2}$
$s = 0 \times 1 + \frac{1}{2} \times 10 \times 1^{2}$
s = 5 m
Now, average speed of a body is the total distance travelled upon the total time taken by the body.
So, average speed $= \frac{5}{1} = 5 \frac{m}{s}$

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A child drops a toy from the top of a building, it takes 1 s to reach the ground. Find the height of the building and the average speed of the toy? Take g=10ms2

The correct option is B 5 m and 5 m/s Since, u = 0 and a = 10 m/s2 s = ut + 12at2​ s=0×1+12×10×12​​ s = 5 m Now, average speed of a body is the total distance travelled upon the total time taken by the body. So, average speed =51=5ms

A child drops a toy from the top of a building, it takes 1 s to reach the ground. Find the height of the building and the average speed of the toy? $T a k e g = 10 \frac{m}{s^{2}}$