A child has a block in the shape of a cube with one letter written on each face as shown. If the cube is thrown once, what is the probability of getting A?

\frac{1}{26}

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\frac{1}{3}

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\frac{1}{52}

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\frac{1}{14}

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Solution

The correct option is B $\frac{1}{3}$
There are six faces, two of which are A, so the probability of getting A is $\frac{2}{6} = \frac{1}{3}$ .

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