Question

A child has a die whose six faces show the letters as given below:
The die is thrown once.



(i) What is the probability of getting A?
(i) What is the probability of getting B?

Answer 1

Number of faces in a die is 6

$\therefore$ n(S) = 6
(i) The probability of getting face 'A':
$\because$ n(E) = 2
$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{2}{6}=\frac{1}{3}$
Probability of getting A is $\frac{1}{3}$
(ii) The probability of getting face 'B':
$\because$ n(E) = 1
$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{1}{6}=\frac{1}{6}$
Probability of getting B is $\frac{1}{6}$