Question

A child is looking for his father. He went 90 meters in the East before turning to his right. He went 20 meters before turning to his right again to look for his father at his uncle's place 30 meters from this point. His father was not there. from there he went 100 meters to the North before meeting his father in a street. How far from the starting point did the son meet his father?

• A. 80 meters
• B. 100 meters
• C. 140 meters
• D. 260 meters

Answer 1

The correct option is B 100 meters

Clearly, the child moves from A to B $90$ metres eastwards upto B, then turns right and moves $20$ meters upto C, then turns right and moves $30$ metre upto D. Finally he moves towards North for $100$ metres upto E where he meets his father.
So $AB=90$ metre, $BF=CD=$ $30$ metre,
So, $AF=AB-BF=$ $60$ metres
Also $DE=$$100$ metres

$DF=BC=$ $20$ metres
So, $EF=DE-DF=$ $100-20$ = $80$ metres
In right angled $△$ AFE
$AE$ = $\sqrt{A{F}^2+E{F}^2}$ = $\sqrt{{60}^2+{80}^2}$ =$100$ meters
So from starting point his father was 100 metre away.

option B