Question

A child is looking for his father He went 90 metres in the East before turning to his right He went 20 metres before turning to his right again to look for his father at his uncle's place 30 metres from this point His father was not there From here he went 100 metres to the North before meeting his father in a street How far did the son meet his father from the starting point ?

• A. 80 meters
• B. 100 meters
• C. 140 meters
• D. 260 meters

Answer 1

The correct option is B 100 meters

The movements of the child from A to E are as shown in fig
Clearly the child meets his father at E
Now AF = (AB - FB) = (AB - DE) = (90-30)m = 60 m
EF = (DE-DF) = (DE-BC) = (100-20) m = 80 m
∴∴ Required distance
=AE=AF2+EF2−−−−−−−−−−√=(60)2+(80)2−−−−−−−−−−√=AE=AF2+EF2=(60)2+(80)2
3600+6400−−−−−−−−−−√=10000−−−−−√=100m