A child is moving on a skateboard at a speed of 2 m/s. After a force acts on him, his speed becomes 3 m/s. What is the work done by the external force, given the mass of the object is 20 kg?
10 J
Let initial velocity of the child be v1 and final velocity be v2
v1=2 ms−1
v2=3 ms−1
Since the child is in motion, he will have a kinetic energy of mv22, which will be increased after the application of force by the external agent on him.
According to work energy theoram,
Work done by the external force on the child = Change in kinetic energy of the child =mv222–mv212
=20×(9–4)2
=10×5=50 J