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Question

A child is standing at one end of a long trolley moving with a speed 'v' on a smooth horizontal track. If the child starts running towards the other end of the trolley with a speed 'u', the centre of mass of the system (trolley + child) will move with a speed

A
zero
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B
(v + u)
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C
(v - u)
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D
v
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Solution

The correct option is D v
The speed of the centre of mass of the system will remain unchanged (=v). The speed of the centre of mass of a system can change only if a net external force acts on it. The forces involved (such as the action and reaction and frictional forces), when the child runs on the trolley, are internal to the (trolley + child) system.

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