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Question

A child pulls a suitcase through a distance 10 m on a smooth horizontal floor. The handle held in child's hand makes an angle θ with horizontal surface. If a 5 N force is applied and the horizontal component is half of the applied force.
Work done by child in pulling suitcase is

A
50 J
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B
60 J
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C
25 J
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D
45 J
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Solution

The correct option is C 25 J
Component of apllied force in the direction of motion
=12×applied force =12×5=2.5 N

Work done (W) = Compound of applied force in the direction of motion × displacement
=2.5×10=25 J
Thus, work done is 25 Joule.

Positive work done means direction of component of the apllied force is in the direction of displacement.


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