A child pulls a suitcase through a distance 10 m on a smooth horizontal floor- The handle held in child-s hand makes an angle - with horizontal surface- If a 5 N force is applied and the horizontal component is half of the applied force-Work done by child in pulling suitcase is

Component of apllied force in the direction of motion =12×applied force=12× 5=2.5 N Work done (W) = Compound of applied force in the direction of motion × disp ...

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Byju's Answer

Standard IX

Physics

Displacement

A child pulls...

Question

A child pulls a suitcase through a distance 10 m on a smooth horizontal floor. The handle held in child's hand makes an angle $θ$ with horizontal surface. If a 5 N force is applied and the horizontal component is half of the applied force.
Work done by child in pulling suitcase is

50 J

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60 J

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25 J

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45 J

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Solution

The correct option is C $25 J$
Component of apllied force in the direction of motion
= $\frac{1}{2} \times applied force = \frac{1}{2} \times 5 = 2.5 N$

Work done (W) = Compound of applied force in the direction of motion $\times$ displacement
$= 2.5 \times 10 = 25 J$
Thus, work done is 25 Joule.

Positive work done means direction of component of the apllied force is in the direction of displacement.

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A child pulls a suitcase through a distance 10 m on a smooth horizontal floor. The handle held in child's hand makes an angle θ with horizontal surface. If a 5 N force is applied and the horizontal component is half of the applied force. Work done by child in pulling suitcase is

A child pulls a suitcase through a distance 10 m on a smooth horizontal floor. The handle held in child's hand makes an angle $θ$ with horizontal surface. If a 5 N force is applied and the horizontal component is half of the applied force.
Work done by child in pulling suitcase is