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Question

A child pushes a 2.2 kg swing that is initially at rest. The net force on the swing over time is shown below.


What is the swing's speed at t=40 ms? Round off the answer to two decimal places.

A
0.36 m/s
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B
0.48 m/s
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C
0.15 m/s
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D
0.26 m/s
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Solution

The correct option is A 0.36 m/s
Area under force vs. time graph gives change in momentum ΔP.
F.dt=ΔP=PfPi
Area under graph =12×base×height
=12×40×103×40
ΔP=12(0.040 s)(40 N)=0.80 kg m/s
We can use the change in momentum to solve for the final speed,
ΔP=mΔv
Δv=ΔPm
vf0=(0.80 kg ms)2.2 kg
vf0.363 m/s
Rounded off to two significant figures, the final speed of the swing is 0.36 m/s

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