Question

A child’s game has 8 triangles of which 3 are blue and rest are red and 10 squares of which 6
are blue and rest are red. One piece is lost at random. Find the probability that it is a:
(i) triangle (ii) square
(iii) square of blue of colour (iv) triangle of red colour

Answer 1

Answer :

we know Probability P ( E ) = $\frac{Totalnumberofdesiredeventsn(E)}{Totalnumberofeventsn(S)}$

Here Total number of events ( Total games ) n ( S ) = 8 + 10 = 18

i ) One piece is lost at random. Find the probability that it is a triangle .

So,

Total number of triangles = 8 , So n ( E ) = 8

And
Probability = $\frac{8}{18}=\frac{\mathbf{4}}{\mathbf{9}}\mathbf{(}\mathbf{}\mathit{A}\mathit{n}\mathit{s}\mathbf{}\mathbf{)}$

ii ) One piece is lost at random. Find the probability that it is a square .

So,

Total number of squares = 10 , So n ( E ) = 10

And
Probability = $\frac{10}{18}=\frac{\mathbf{5}}{\mathbf{9}}\mathbf{(}\mathbf{}\mathit{A}\mathit{n}\mathit{s}\mathbf{}\mathbf{)}$

iii ) One piece is lost at random. Find the probability that it is a square of blue of colour .

So,

Total number of square of blue of colour = 6 , So n ( E ) = 6

And
Probability = $\frac{6}{18}=\frac{\mathbf{1}}{\mathbf{3}}\mathbf{(}\mathbf{}\mathit{A}\mathit{n}\mathit{s}\mathbf{}\mathbf{)}$

iv ) One piece is lost at random. Find the probability that it is a triangle of red colour .

So,

Total number of triangle of red colour = 5 , So n ( E ) = 5

And
Probability = $\frac{\mathbf{5}}{\mathbf{18}}\mathbf{(}\mathbf{}\mathit{A}\mathit{n}\mathit{s}\mathbf{}\mathbf{)}$