A China dish weighs 25 g when empty. When saturated solution of potassium chloride is poured into it at 40^oC,the weight of the dish is 63 g. When the solution is evaporated to dryness, the China dish along with crystals weighs 40 g. Find the solubility of potassium chloride at 40^oC.

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Solution

$W e i g h t o f s a t u r a t e d s o l u t i o n = 63 - 25 = 38 g W e i g h t o f c r y s t a l s = 40 - 25 = 15 g W e i g h t o f w a t e r i n t h e s a t u r a t e d s o l u t i o n = 38 - 15 = 23 g S o l u b i l i t y o f p o t a s s i u m c h l o r i d e = \frac{W e i g h t o f c r y s t a l s}{W e i g h t o f w a t e r} \times 100 = \frac{15}{23} \times 100 = 65 g / 100 g o f w a t e r a t 40^{0} C$

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A China dish weighs 25 g when empty. When saturated solution of potassium chloride is poured into it at 40oC,the weight of the dish is 63 g. When the solution is evaporated to dryness, the China dish along with crystals weighs 40 g. Find the solubility of potassium chloride at 40oC.

Weight of saturated solution =63 - 25 = 38 gWeight of crystals = 40 - 25 = 15 gWeight of water in the saturated solution = 38 - 15 = 23 gSolubility of potassium chloride = Weight of crystalsWeight of water × 100 = 1523 × 100 = 65 g / 100 g of water at 40 0C

A China dish weighs 25 g when empty. When saturated solution of potassium chloride is poured into it at 40^oC,the weight of the dish is 63 g. When the solution is evaporated to dryness, the China dish along with crystals weighs 40 g. Find the solubility of potassium chloride at 40^oC.