A chord 8 cm long is at a distance of 3 cm from the centre of a circle. Then the radius of that circle is

4 cm

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6 cm

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3 cm

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5 cm

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Solution

The correct option is D
5 cm

The perpendicular distance between the centre of the circle to the chord = 3 cm

The line droped from centre of the circle to the chord bisects it.

Radius = $\sqrt{3^{2} + 4^{2}} = \sqrt{25} = 5 c m$

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