Number of Common Tangents to Two Circles in Different Conditions
A chord AB is...
Question
A chord AB is drawn from the point A(0,3) on the circle x2+4x+(y−3)2=0, and is extended to M such that AM=2AB. The locus of M is
A
x2+y2−8x−6y+9=0
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B
x2+y2+8x+6y+9=0
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C
x2+y2+8x–6y+9=0
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D
x2+y2–8x+6y+9=0
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Solution
The correct option is Cx2+y2+8x–6y+9=0 Let the coordinates of M(h,k) Then the coordinates of B=(h+02,k+32) As B lies on the circle, so h24+2h+(k−3)24=0⇒h2+8h+k2−6k+9=0