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Question

A chord AB of a circle whose centre is O, is bisected at E by a diameter CD. OC= OD = 15cm and OE = 9 cm. Find the length of AB


A

Rectangle

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B

Square

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C

Rhombus

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D

Circle

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Solution

The correct option is D

Circle


Given OE = 9 cm, OA = 15cm

Consider OAE, OEA=90o

Applying Pythagoras theorem

AE2 = OA2 OE2

AE2 = 152 92

AE2 = 225 81 =144

AE=12cm

AB=2 × 12 = 24cm [the perpendicular from the centre bisects the chord]


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