A chord attached to a vibrating form divides it into $6$ loops, when its tension is $36 N$ . The tension at which it will vibrate in $4$ loops is

24 N

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36 N

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64 N

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81 N

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Solution

The correct option is C $81 N$
Frequencies are same in both the cases. Frequency $f = \frac{n}{2 L} (\sqrt{(T / m)})$ , $n$ = number of loops, $T$ = tension
$f = f^{'}$
=> $\frac{6}{2 L} (\sqrt{(36 / m)}) = \frac{4}{2 L} (\sqrt{(T^{'} / m)})$
$T^{'} = 81 N$

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A chord attached to a vibrating form divides it into 6 loops, when its tension is 36N. The tension at which it will vibrate in 4 loops is

The correct option is C 81NFrequencies are same in both the cases. Frequency f=n2L(√(T/m)), n = number of loops, T = tensionf=f′=> 62L(√(36/m))=42L(√(T′/m))T′=81N

A chord attached to a vibrating form divides it into $6$ loops, when its tension is $36 N$ . The tension at which it will vibrate in $4$ loops is

The correct option is C $81 N$
Frequencies are same in both the cases. Frequency $f = \frac{n}{2 L} (\sqrt{(T / m)})$ , $n$ = number of loops, $T$ = tension
$f = f^{'}$
=> $\frac{6}{2 L} (\sqrt{(36 / m)}) = \frac{4}{2 L} (\sqrt{(T^{'} / m)})$
$T^{'} = 81 N$