Question

A chord of a circle of radius $10cm$ subtends a right angle at the centre. Find the area of the corresponding:
major sector. (Use $\pi =3.14$)

Answer 1

Radius of the circle, $r=10cm$.
Angle at the centre of circle, $\theta ={90}^o$
1) Area of minor segment=?
2) Area of major segment=?
(iii) Area of the major segment $\left(AQBO\right)$.
$=\frac{\theta }{360}\times p{r}^2$
$=\frac{(360-90)}{360}\times 3.14\times (10{)}^2$
$=\frac{270}{360}\times 3.14\times 100$
$=\frac{3}{4}\times 3.14\times 100$
$=\frac{3}{4}\times 314$
$=235.5c{m}^2$