Question

A chord of a circle of radius 12 cm subtends an angle of ${120}^0$ at the centre. Find the area of the corresponding segment

Answer 1

REF.image

Area of segment = Area of circle $\times \frac{{120}^{\circ }}{{360}^{\circ }}$

$=\frac{\pi r^2}{3}=\frac{3.14\times {12}^2}{3}$

$=3.14\times 48=150.72c{m}^2$