A chord of a circle of radius 12cm subtends an angle of 60o at the centre. Find the area of the corresponding segment of the circle. (Use π=3.14 and √3=1.73).
A
17.43cm2
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B
13.08cm2
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C
11.66cm2
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D
9.64cm2
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Solution
The correct option is B13.08cm2 Here r=12cm, θ=60o Area of the corresponding segment ABXA =[πr2θ360−12r2sinθ] =[3.14×12×12×60o360o−12×12×sin60o] =[314100×12×2−6×12×√32]cm2. [∵sin60o=√32] =[7536100−36×1.73]cm2 =[75.36−62.28]cm2=13.08cm2