Question

A chord of a circle of radius $28cm$ subtends a right angle at the center. What is the area of the minor sector?

Answer 1

Given, central angle​, $\theta ={90}^{\circ }$

and, Radius, $r=28cm$​

Area of minor sector $=\frac{\theta }{{360}^{\circ }}\times \pi r^2$​

$=\frac{90}{360}\times \frac{22}{7}\times 28\times 28$​

$=\frac{1}{4}\times 22\times 4\times 28$​

$=616c{m}^2$