Question

A chord of a circle of radius 6 cm subtends an angle of ${60}^{\circ }$ at the centre of the circle. The area of the minor segment is
(use $\pi =3.14$)

• A. 6.54 $c{m}^2$
• B. 0.327 $c{m}^2$
• C. 7.25 $c{m}^2$
• D. 3.27 $c{m}^2$

Answer 1

The correct option is D 3.27 $c{m}^2$

$\theta ={60}^{\circ }$, r = 6 cm
Area of minor segment = $\frac{36}{2}[\frac{60\times 3.14}{180}-\frac{\sqrt{3}}{2}]$
= 3.27 $c{m}^2$