A chord of length 8cm is drawn at a distance of 3cm from the centre of a circle. Calculate the radius of the circle.
A
3cm
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B
5cm
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C
6cm
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D
8cm
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Solution
The correct option is A5cm LetA circle with center O and a chord AB of length 8cm A perpendicular from centre of the circle to chord divides the chord in two equal parts Let the perpendicular from centre meets the chord at point C hence AC=CB=4 OC=3 sinceOAC is a right angle triangle so using Pythagorean Theorem OA2=AC2+OC2 ⇒OA2=42+32 ∴OA=√16+9=√25=5cm