A chord of length 8 cm is drawn in a circle of radius 5 cm. Calculate its distance from the centre of the circle.
3 cm
Let chord AB = 8cm
⇒AC = CB = 4cm [ the perpendicular from the centre of the circle bisects the chord]
△OAC is a right angled triangle.
∴ OC2=OA2−AC2
= 52−42
= 25 - 16 = 9
∴ OC=√9 = 3cm