A circle has area which is 16 times the area of another circle The ratio of their circumference is

4:1

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8:1

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16:1

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None

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Solution

The correct option is A 4:1
Let $r_{1}$ be the radius of the first circle and $r_{2}$ and be the
radius of the second circle.

Given, Area of first circle $= 16 \times$ Area of second circle
$=> p i {r_{1}}^{2} : 16 π {r_{2}}^{2}$
$= {r_{1}}^{2} : 16 {r_{2}}^{2}$
$=> r_{1} : r_{2} = 4 : 1$
Ratio of their circumference $= 2 π r_{1} : 2 π r_{2} = r_{1} : r_{2} = 4 : 1$

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