Question

A circle has its centre at the origin and a point P(5,0) lies on it. Then the point (6,8) lies

• A. outside the circle
• B. inside the circle
• C. on the circle

Answer 1

The correct option is A outside the circle

As the centre is (0,0) and (5,0) is on the circle. Therefore the radius of the circle is 5 units.
Distance between (6,8) and centre of the circle = $\sqrt{(6-0{)}^2+(8-0{)}^2}=\sqrt{6^2+8^2}=\sqrt{100}=10units.$

Since the distance between (6,8) and centre of the circle is greater than 5 units, the point (6,8) lies outside the circle.