A circle has its centre at the origin and a point P(5,0) lies on it. The point Q(6,8) lies
First, we draw a circle and a point from the given information.
∵ The distance between two points (x1,y1) and (x2,y2) is √(x2−x1)2+(y2−y1)2
∴ Distance between origin i.e., O(0,0) and P(5,0), PO=√(5−0)2+(0−02)
=√(x2−x1)2+(x2−y1)2
=√52+02=5=Radius of circle
Distance between origin O(0,0) and Q(6,8) OQ is=√(6−0)2+(8−0)2
=√(62+82)=√36+64=√100=10
If the distance of any point from the centre is d and
i) d < radius, then the point is inside the circle
ii) d > radius, then the point is on the circle
iii) d = radius, then the point is outside the circle
Here, we see that, OQ > OP
Hence,the point Q(6,8), lies outside the circle.