The correct option is B outside the circle
The centre of the circle is at (0, 0) and (5, 0) lies on the circle.
So, the radius of the circle = |5 − 0| = 5 units.
Distance between (6, 8) and centre of the circle = √(6−0)2+(8−0)2=√62+82=√100=10 units.
So, the distance between (6, 8) and centre of the circle is greater than radius of the circle.
Hence, the point (6, 8) lies outside the circle.