Question

A circle having diameter 12 cm is cut by a chord of 6 cm, Find the area of smaller arc?

• A. undefined
• B. undefined
• C. undefined
• D. undefined

Answer 1

It can be seen that triangle OAB is equilateral triangle and hence angle AOB = 60 deg.
Therefore, the area of minor arc $AOB=PIx{r}^2\times \frac{60}{360}$
$=pix{6}^2\times \frac{1}{6}=6pisqcm.$