A circle is inscribed in a Δ ABC touching AB, BC and AC at P, Q and R respectively. If AB = 10 cm, AR = 7 cm and CR = 5 cm, find the length of BC.
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Solution
A circle is inscribed in a triangle ABC touching AB, BC and CA at P, Q and R respectively.
Also, AB = 10 cm, AR = 7cm, CR = 5cm AR, AP are the tangents to the circle AP = AR = 7cm AB = 10 cm BP = AB – AP = (10 – 7) = 3 cm Also, BP and BQ are tangents to the circle BP = BQ = 3 cm Further, CQ and CR are tangents to the circle CQ = CR = 5cm BC = BQ + CQ = (3 + 5) cm = 8 cm Hence, BC = 8 cm