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Question

State True or False.

The parallelogram circumscribing a circle is a rhombus.


A

5cm

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B

False

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Solution

The correct option is A

5cm


A parallelogram ABCD circumscribes a circle with centre O.

We know that the lengths of tangents drawn from an exterior point to a circle are equal.

AP = AS, . . . (i) [tangents from A]

BP = BQ, . . . (ii) [tangents from B]

CR = CQ, . . . (iii) [tangents from C]

DR = DS . . . (iv) [tangents from D]

Adding (i), (ii), (iii) and (iv), we get,

AP + BP + CR + DR = AS + DS + BQ + CQ

AB + CD = AD + BC . . . (v)

But we know that in a parallelogram opposite sides are equal.

AD = BC and AB = CD, putting these in (v) we get

2 AB = 2 AD

AB = AD = CD = BC.

Hence, ABCD is a rhombus.


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