A circle is kept in a square as shown, what is the probability that the point chosen doesn't lie in the circle?

(π-3)/4

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(5-π)/4

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(4-π)/4

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(π-2)/4

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Solution

The correct option is C
(4-π)/4

Let the side length of the square be a
Radius of the circle is $\frac{a}{2}$
Total area $= a^{2}$
Favorable area $= a^{2} - π {(\frac{a}{2})}^{2}$
Probability $= \frac{f a v o r a b l e a r e a}{t o t a l a r e a}$
$= \frac{4 - π}{4}$

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