A circle of diameter 13 cm has two chords of length 12 cm and 5 cm. If both the chords lie in the same semi-circle, what is the distance between the chords?
3.5 cm
Here, r=132 cm=6.5 cm
OP=√(132)2−(122)2=√1694−1444 [Perpendicular from the centre bisects the chord]
=52 cm
OQ=√(132)2−(52)2=√1694−254
=122=6 cm
∴PQ=OQ−OP=6−52=72=3.5 cm