Question

A circle of diameter 6 cm makes a sector of angle $P^{\circ }$, what will be the area of the sector?

• A. (P/ 720⁰) ×π × 3²
• B. (P/ 360⁰) ×π × 3²
• C. (P/ 360⁰) ×π × 6²
• D. (P/ 180⁰) ×π × 3²

Answer 1

The correct option is B

(P/ 360⁰) ×π × 3²

Area of a sector of angle $\theta$

= $\frac{\theta }{360}$ × $\pi \times r^2$

Here radius, r=3

$\to$ $\frac{P}{360}$ × $\pi \times 3^2$