A circle of radius ‘5’ touches the coordinate axes in the first quadrant. If the circle makes one complete roll on x-axis along the positive direction, then its equation in new position is
Intial centre of the circle is c=(5,5) and after completing one complete revolution the centre of the circel is 5+!0π
So the equation of the circle in the new position is (x−5−10π)2+(y−5)2=52