A circle passes through the origin and has its centre on y=x. If it cuts x2+y2−4x−6y+10=0 orthogonally, then show that the equation of the circle is x2+y2−2x−2y=0.
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Solution
Since the circle passes through origin c=0, its centre lies on y=x∴g=f. It cuts orthogonally the given circle ∴2g(−2)+2f(−3)=10+0 But g=f ∴g=−1=f and c=0.