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Question

A circle passes through the point (1,2) and touches both the axes line Find its equation.

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Solution

Let the equation of circle be x2+y2+2gx+2fy+c=0
Passes through (1,2)1+4+2g+4f+c=0(1)
Touches xaxisg2=c(2)
Touches yaxisf2=c(3)
From (2)(3)g=f
Put it in (1)
5+2g+4g+g2=0g2+6g+5=0g2+5g+g+5=0g(g+5)+1(g+5)=0(g+5)(g+1)=0g=1,5f=1,5c=1,25
So the required equation of circles are x2+y210x10y+25=0x2+y22x2y+1=0


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