A circle touches all the four sides of a quadrilateral ABCD with AB=10cm, BC=8cm and CD=6cm.Find AD.

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Solution

The correct option is A
8

Since tangents drawn from an exterior point to a circle are equal in length.

So, AB + CD = BC + DA

10 + 6 = 8 + DA

So, DA = 16 - 8

= 8 cm

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A circle touches all the four sides of a quadrilateral ABCD with AB=10cm, BC=8cm and CD=6cm.Find AD.

The correct option is A 8Since tangents drawn from an exterior point to a circle are equal in length. So, AB + CD = BC + DA 10 + 6 = 8 + DA So, DA = 16 - 8 = 8 cm

The correct option is A
8

Since tangents drawn from an exterior point to a circle are equal in length.

So, AB + CD = BC + DA

10 + 6 = 8 + DA

So, DA = 16 - 8

= 8 cm