A circle touches the side BC of a $Δ$ ABC at P and AB produced at Q and AC produced at R. If the perimeter of the triangle is 12cm. then length $(A Q + A R)$ is equal to

8 cm.

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10 cm.

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12 cm.

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15 cm.

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Solution

The correct option is C 12 cm.
$A B + B C + A C = 12$ ,
$A B + B P + P C + A C = 12$
$∵ A Q = A R \Rightarrow A B + B Q = A C + C R$
$A B + B P = A C + P C$

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