A circle touches $X$ axis at $+ 3$ distance and cuts an intercept of $8$ in $+ v e$ direction of $y$ axis. Its equation is

x^{2} + y^{2} + 6 x + 10 y - 9 = 0

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x^{2} + y^{2} - 6 x - 10 y - 9 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} - 6 x - 10 y + 9 = 0

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x^{2} + y^{2} + 6 x + 10 y + 9 = 0

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Solution

The correct option is A $x^{2} + y^{2} - 6 x - 10 y + 9 = 0$
Circle touches X- axis at $(3, 0)$
Circle cuts intercept of $8$ in $+ v e$ direction.
$g = 3$
$r^{2} = 4^{2} + 3^{2}$
$r = 5$
$f = 5$
Circle $\to (x - 3)^{2} + (y - 5)^{2} = 5^{2}$
$x^{2} + y^{2} - 6 x - 10 y + 9 = 0$
C is correct .

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A circle touches X axis at +3 distance and cuts an intercept of 8 in +ve direction of y axis. Its equation is

The correct option is A x2+y2−6x−10y+9=0Circle touches X- axis at (3,0)Circle cuts intercept of 8 in +ve direction.g=3r2=42+32r=5f=5Circle →(x−3)2+(y−5)2=52x2+y2−6x−10y+9=0C is correct .

A circle touches $X$ axis at $+ 3$ distance and cuts an intercept of $8$ in $+ v e$ direction of $y$ axis. Its equation is

The correct option is A $x^{2} + y^{2} - 6 x - 10 y + 9 = 0$
Circle touches X- axis at $(3, 0)$
Circle cuts intercept of $8$ in $+ v e$ direction.
$g = 3$
$r^{2} = 4^{2} + 3^{2}$
$r = 5$
$f = 5$
Circle $\to (x - 3)^{2} + (y - 5)^{2} = 5^{2}$
$x^{2} + y^{2} - 6 x - 10 y + 9 = 0$
C is correct .